In the circuit diagram shown,each battery is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. By applying nodal analysis to the circuit,we determine the potentials at different nodes. Let the potential at the rightmost node be $0\ V$.

Vedclass · Accepted Answer

$1\ A, 22\ W$

Vedclass · Answer

(A) $1$. By applying nodal analysis to the circuit,we determine the potentials at different nodes. Let the potential at the rightmost node be $0\ V$. Based on the circuit configuration and the given ideal batteries of $1\ V$ each,we find the currents flowing through each branch.$2$. The ammeter is in series with a $1\ V$ battery and a $1\ \Omega$ resistor. The current through the ammeter branch is calculated to be $1\ A$.$3$. The total thermal power $P$ dissipated in the resistors is given by the sum of $I^2R$ for each resistor in the circuit.$4$. Based on the current distribution: $P = (3^2 	imes 1) + (2^2 	imes 1) + (2^2 	imes 1) + (2^2 	imes 1) + (1^2 	imes 1) = 9 + 4 + 4 + 4 + 1 = 22\ W$.

In the circuit diagram shown,each battery is ideal having an e.m.f. of $1\ V$. Each resistor has a resistance of $1\ \Omega$. The ammeter $(A)$ has a resistance of $1\ \Omega$. Find the reading of the ammeter and the total thermal power produced in the circuit.

Similar Questions

The potential difference between point $A$ and $B$ is ............. $V$.

In the given circuit,the current flowing through the circuit is: (in $A$)

$A, B$ and $C$ are voltmeters of resistance $R, 1.5R$ and $3R$ respectively as shown in the figure. When some potential difference is applied between $X$ and $Y$,the voltmeter readings are $V_A, V_B$ and $V_C$ respectively. Then

Vedclass Test Series

Exam Paper Generator

Online Exam Module